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min_avg_two_slice.py
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"""
A non-empty zero-indexed array A consisting of N integers is given.
A pair of integers (P, Q), such that 0 ≤ P < Q < N, is called a slice of array A
(notice that the slice contains at least two elements).
The average of a slice (P, Q) is the sum of A[P] + A[P + 1] + ... + A[Q]
divided by the length of the slice. To be precise, the average equals
(A[P] + A[P + 1] + ... + A[Q]) / (Q − P + 1).
For example, array A such that:
A[0] = 4
A[1] = 2
A[2] = 2
A[3] = 5
A[4] = 1
A[5] = 5
A[6] = 8
contains the following example slices:
slice (1, 2), whose average is (2 + 2) / 2 = 2;
slice (3, 4), whose average is (5 + 1) / 2 = 3;
slice (1, 4), whose average is (2 + 2 + 5 + 1) / 4 = 2.5.
The goal is to find the starting position of a slice whose average is minimal.
Write a function:
def solution(A)
that, given a non-empty zero-indexed array A consisting of N integers,
returns the starting position of the slice with the minimal average.
If there is more than one slice with a minimal average,
you should return the smallest starting position of such a slice.
For example, given array A such that:
A[0] = 4
A[1] = 2
A[2] = 2
A[3] = 5
A[4] = 1
A[5] = 5
A[6] = 8
the function should return 1, as explained above.
Assume that:
N is an integer within the range [2..100,000];
each element of array A is an integer within the range [−10,000..10,000].
Complexity:
expected worst-case time complexity is O(N);
expected worst-case space complexity is O(N), beyond input storage
(not counting the storage required for input arguments).
Elements of input arrays can be modified.
"""
import sys
def solution(A):
n = len(A)
pre_sum = [0] * (n + 1)
min_slice_avg = sys.maxsize
min_slice_idx = 0
for i in range(1, n + 1):
pre_sum[i] = pre_sum[i - 1] + A[i - 1]
# calculate at least 2 prefix sums
if i - 2 < 0:
continue
# check prev 3 slices if we have calculated 3 prefix sums
if i >= 3:
prev_3_slice_avg = (pre_sum[i] - pre_sum[i - 3]) / 3.0
if prev_3_slice_avg < min_slice_avg:
min_slice_avg = prev_3_slice_avg
min_slice_idx = i - 3
# check prev 2 slices
prev_2_slice_avg = (pre_sum[i] - pre_sum[i - 2]) / 2.0
if prev_2_slice_avg < min_slice_avg:
min_slice_avg = prev_2_slice_avg
min_slice_idx = i - 2
return min_slice_idx