Adding java code for Push Zero

1. Array/push_zero/PushZeroArnab.java

@@ -0,0 +1,65 @@
+/**
+ * PushZero.java
+ * Given an array of integers,rearrange the array such that all zeroes are at the end without disturbing the orginal
+   sequence
+ * Description- 
+ * Take the values of input and check if its non zero or not,If non-zero,then apend them to solution,else count the 
+   No of occurences.The at the end,append the no of zeroes of that count.
+ * Time Complexity-O(n) Extra Space Complexity-O(1)
+ * @author [codebook-2000] (https://github.com/codebook-2000)
+ */
+import java.util.*;
+import java.lang.*;
+import java.io.*;
+
+public class PushZeroArnab
+{
+    static void solve(int arr[],int n)
+    {
+        int index=0,j=0;
+        while(j<n)
+        {
+            if(arr[j]!=0)
+            {
+                arr[index]=arr[j];         //Non zero elements are stored at the beginning
+                index++;
+            }
+            j++;
+        }
+        for(j=index;j<n;j++)
+            arr[j]=0;          //Rest indices are the left zeroes
+    }
+    public static void main (String[] args) throws java.lang.Exception
+    {
+        // your code goes here
+        BufferedReader buf=new BufferedReader(new InputStreamReader(System.in));
+        int t=Integer.parseInt(buf.readLine());
+        StringBuilder sb=new StringBuilder();
+        for(int i=0;i<t;i++)
+        {
+            int n=Integer.parseInt(buf.readLine()); //Reading the input
+            String st1[]=(buf.readLine()).split(" ");
+            int arr[]=new int[n];
+            for(int j=0;j<n;j++)
+                arr[j]=Integer.parseInt(st1[j]);
+            solve(arr,n);  //Calling the method solve each time
+            for(int j=0;j<n;j++)
+                sb.append(arr[j]+" ");
+            sb.append("\n");
+        }
+        System.out.println(sb);  //Printing it
+    }
+}
+/*
+input:-
+2
+5
+1 0 2 0 3
+6
+0 5 6 9 0 3
+*/
+/*
+output:-
+1 2 3 0 0 
+5 6 9 3 0 0
+*/